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For how many integers n is n + n = n*n ?

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For how many integers n is n + n = n*n ? [#permalink]

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For how many integers n is n + n = n*n ?

a) None
b) One
c) Two
d) Three
e) More than three.

Originally posted by alanforde800Maximus on 10 Oct 2016, 06:52.
Last edited by Bunuel on 10 Oct 2016, 07:29, edited 1 time in total.
Renamed the topic, edited the question and the OA.
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Re: For how many integers n is n + n = n*n ? [#permalink]

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New post 10 Oct 2016, 07:21
alanforde800Maximus wrote:
For how many integers n is n + n = n.n ?

a) None
b) One
c) Two
d) Three
e) More than three.

Please assist with above problem.


Is it \(n + n=n*n\)? In this case the OA cannot be D, it should be C:
2n = n^2
n(2-n) = 0
n = 0 or n = 2.
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Re: For how many integers n is n + n = n*n ? [#permalink]

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New post 10 Oct 2016, 07:24
Correct. OA mentioned is incorrect. Answer should be C. n=0 and n =2
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Re: For how many integers n is n + n = n*n ? [#permalink]

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New post 10 Oct 2016, 07:26
Bunuel wrote:
alanforde800Maximus wrote:
For how many integers n is n + n = n.n ?

a) None
b) One
c) Two
d) Three
e) More than three.

Please assist with above problem.


Is it \(n + n=n*n\)? In this case the OA cannot be D, it should be C:
2n = n^2
n(2-n) = 0
n = 0 or n = 2.


Hello Bunuel,

yes it is n+n=n∗n and OA is C only.

Thanks for reply.
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Re: For how many integers n is n + n = n*n ? [#permalink]

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New post 26 Oct 2017, 15:42
alanforde800Maximus wrote:
For how many integers n is n + n = n*n ?

a) None
b) One
c) Two
d) Three
e) More than three.


Simplifying the equation, we have:

2n = n^2

n^2 - 2n = 0

n(n - 2) = 0

n = 0 or n = 2, so there are two possible integer values for n.

Answer: C
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Re: For how many integers n is n + n = n*n ?   [#permalink] 26 Oct 2017, 15:42
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