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For how many positive integer x is 130/x an integer?

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For how many positive integer x is 130/x an integer?  [#permalink]

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New post 22 May 2017, 05:59
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Re: For how many positive integer x is 130/x an integer?  [#permalink]

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New post 22 May 2017, 06:23
8 as 130= 13*2*5
no.of factors = 2*2*2=8
Hence answer should be A


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For how many positive integer x is 130/x an integer?  [#permalink]

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New post 22 May 2017, 06:26
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Bunuel wrote:
For how many positive integer x is 130/x an integer?

(A) 8
(B) 7
(C) 6
(D) 5
(E) 3


In order for 130/x to be an integer, x must be a divisor of 130

So, the question is really asking us to determine the number of positive divisors of 130.
To do this, we can use the following rule:
If the prime factorization of N = (p^a)(q^b)(r^c) . . . (where p, q, r, etc are different prime numbers), then N has a total of (a+1)(b+1)(c+1)(etc) positive divisors.

Example: 14000 = (2^4)(5^3)(7^1)
So, the number of positive divisors of 14000 = (4+1)(3+1)(1+1) =(5)(4)(2) = 40

Now onto the question.......
130 = (2)(5)(13) = (2^1)(5^1)(13^1)
So, the number of positive divisors of 130 = (1+1)(1+1)(1+1) =(2)(2)(2) = 8

Answer:

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Re: For how many positive integer x is 130/x an integer?  [#permalink]

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Re: For how many positive integer x is 130/x an integer?  [#permalink]

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New post 22 May 2017, 08:46
Bunuel wrote:
For how many positive integer x is 130/x an integer?

(A) 8
(B) 7
(C) 6
(D) 5
(E) 3


The factors of 130 are: 1, 2, 5, 10, 13, 26, 65, 130

So, 130 divided by any of the above 8 numbers will result in an integer..

Thus, answer must be (A) 8
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Re: For how many positive integer x is 130/x an integer?  [#permalink]

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New post 23 May 2017, 01:25
It is a direct question of finding no. of factors.
Factorization of any integer = a^p * b^q * c^r (where a,b,c are prime factors and p,q,r are powers of a,b,c respectively).
So on factorization of 130, we get 2^1 * 5^1 * 13^1
No. of factors = (p+1)*(q+1)*(r+1) = 2*2*2 = 8.
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Re: For how many positive integer x is 130/x an integer?  [#permalink]

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New post 25 May 2017, 15:50
Bunuel wrote:
For how many positive integer x is 130/x an integer?

(A) 8
(B) 7
(C) 6
(D) 5
(E) 3


If x is a factor of 130, then 130/x is an integer; thus, we need to determine the number of factors that 130 has.

To do so, we can use the rule in which we prime factorize 130, then add 1 to each exponent of each unique prime factor and then multiply those values together.

130 = 13 x 10 = 13^1 x 5^1 x 2^1

Thus, 130 has (1 + 1)(1 + 1)(1 + 1) = 2 x 2 x 2 = 8 total factors.

Answer: A
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For how many positive integer x is 130/x an integer?  [#permalink]

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New post 13 Oct 2017, 05:28
Bunuel wrote:
For how many positive integer x is 130/x an integer?

(A) 8
(B) 7
(C) 6
(D) 5
(E) 3

This question is a version of "find the number of factors." An integer divided by any of its factors equals an integer.

To find the number of factors of 130 (factors 1 and 130 included)**

1) Do the prime factorization of 130: \(2^1*5^1*13^1\)

2) Take the exponents of each prime factor. Add 1 to each.

Exponents are 1, 1, 1
Add 1 to each, thus: 2, 2, 2

3) Multiply those numbers

2 * 2 * 2 = 8
There are 8 factors of 130*

Answer A

*Factors of 130 are
1, 2, 5, 10, 13, 26, 65, 130
130 divided by any of them yields an integer

**The theory, from Bunuel , SEE THIS POST, scroll down to NUMBER OF FACTORS is, verbatim

Finding the Number of Factors of an Integer

First make prime factorization of an integer \(n=a^p*b^q*c^r\), where \(a\), \(b\), and \(c\) are prime factors of \(n\) and \(p\), \(q\), and \(r\) are their powers.

The number of factors of \(n\) will be expressed by the formula \((p+1)(q+1)(r+1)\). NOTE: this will include 1 and n itself.

Example: Finding the number of all factors of 450: \(450=2^1*3^2*5^2\)

Total number of factors of 450 including 1 and 450 itself is \((1+1)*(2+1)*(2+1)=2*3*3=18\) factors.
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Re: For how many positive integer x is 130/x an integer?  [#permalink]

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New post 13 Oct 2017, 07:03
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Bunuel wrote:
For how many positive integer x is 130/x an integer?

(A) 8
(B) 7
(C) 6
(D) 5
(E) 3


This question is asking us "How many positive divisors does 130 have?"

We can solve this using genxer123's technique or we can just list the divisors IN PAIRS and then count them. We get:
1 and 130
2 and 65
5 and 26
10 and 13

TOTAL = 8 divisors

Answer:

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Re: For how many positive integer x is 130/x an integer?  [#permalink]

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New post 16 Oct 2017, 17:08
Bunuel wrote:
For how many positive integer x is 130/x an integer?

(A) 8
(B) 7
(C) 6
(D) 5
(E) 3


If x is a positive integer and 130/x is an integer, then x must be a factor of 130. Thus, we need to determine the number of factors of 130. To determine the number of factors, we break down 130 into its prime factorization, add 1 to the exponent of each unique prime, and then multiply. Thus:

130 = 10 x 13 = 2^1 x 5^1 x 13^1

Thus, 130 has (1 + 1)(1 + 1)(1 + 1) = 2 x 2 x 2 = 8 total factors.

Answer: A
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Re: For how many positive integer x is 130/x an integer?  [#permalink]

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Re: For how many positive integer x is 130/x an integer?   [#permalink] 01 Oct 2018, 08:05
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