AkamaiBrah wrote:
You should be able to see that you cannot answer this question given the information in the question. Perhaps a more suitable question is:
Given the above information, what is the minimum number of people that own all 5 cars?
This question seems difficult because setting up a Venn diagram is impossible with more than 3 variable (unless you are one of those freaky math or physics majors that think in 4 and 5-D space-time)
Assuming that the question is reworded as above, here is a simple step by step way to get to the solution:
There are 93 beamers and 90 ferraris. Hence, there are
at a minimum 93+90-100 or 83 people with both cars. Agree? (you can set up a venn diagram and come up with this equation quite easily -- leave that as an exercise).
There are at a minimum 83 people with BMW and Ferr and 81 Porsche drivers. Hence there are at a minimum 83 - 81 - 100 or 64 people who drive all 3 cars.
There are at a minimum 64 owning B, F, and P. There are 75 people driving AMs, hence there are at a minimum 64 + 75 - 100 or 39 people driving B,F, P, and AM.
There are at least 39 people driving B,F,P, and AM and 62 people driving Ls. Hence there are at least 62+39-100 = 1 person driving all 5 cars.
QED