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For the past x laps around a track, Stevens avergae time per

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CEO
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For the past x laps around a track, Stevens avergae time per [#permalink]

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New post 18 May 2007, 11:42
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

For the past x laps around a track, Stevens avergae time per lap was 51 seconds. If a lap of 39 seconds would reduce his avg time per lap to 49 seconds, what is the value of x?

Princeton Review uses the "plug the answer choices in and see which one fits" which i dont like. is there an algebraic wa to solve this quickly?

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New post 18 May 2007, 11:47
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[51x+39]/[x+1] = 49

[51x+39]/[x+1] = 49

51x+39 = 49x+49

2x=10

x=5

:-D

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Re: PR Math Algebra [#permalink]

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New post 18 May 2007, 12:34
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bmwhype2 wrote:
For the past x laps around a track, Stevens avergae time per lap was 51 seconds. If a lap of 39 seconds would reduce his avg time per lap to 49 seconds, what is the value of x?

Princeton Review uses the "plug the answer choices in and see which one fits" which i dont like. is there an algebraic wa to solve this quickly?


total time = t

t/x = 51
t = 51x

(t+39)/(x+1) = 49
t = 49x+10

51x = 49x +10
x = 5

Kudos [?]: 170 [1], given: 0

1 KUDOS received
CEO
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Joined: 21 Jan 2007
Posts: 2734

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Re: PR Math Algebra [#permalink]

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New post 18 May 2007, 13:50
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Himalayan wrote:
bmwhype2 wrote:
For the past x laps around a track, Stevens avergae time per lap was 51 seconds. If a lap of 39 seconds would reduce his avg time per lap to 49 seconds, what is the value of x?

Princeton Review uses the "plug the answer choices in and see which one fits" which i dont like. is there an algebraic wa to solve this quickly?


total time = t

t/x = 51
t = 51x

(t+39)/(x+1) = 49
t = 49x+10

51x = 49x +10
x = 5


thanks

sum/n = avg

let t= sum

t/x=51
t=51x

( t+39 ) / (x + 1) = 49
cross multiply. T + 39 = 49x + 49
T = 49x +10

51x = 49x + 10
2x=10
x=5
:lol:

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Re: For the past x laps around a track, Stevens avergae time per [#permalink]

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Re: For the past x laps around a track, Stevens avergae time per   [#permalink] 14 Oct 2017, 04:26
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