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Bunuel
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I agree with PVOG – the logic approach is definitely the easiest way to solve the question.

You divide 3 by some number and get a number that is less than 3. There are only two possible options:

1. Denominator is negative => y - 3 < 0. y < 3
2. Denominator is more than 1 => y -3 > 1. y > 4
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Bunuel
For y ≠ 3, what is the complete solution of the inequality \(\frac{3}{y – 3} < 3\) ?

(A) y > 4
(B) y > 12
(C) y < –1
(D) y < 3
(E) y < 3 or y > 4




Are You Up For the Challenge: 700 Level Questions
What worked for me was assuming two cases one where denominator remains positive i.e, y>4 which give me y>4 & the other set where i flip the sign assuming y<3 which gives y<4 SO y<3....... 4<y & y<3 is the answer
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Bunuel
For y ≠ 3, what is the complete solution of the inequality \(\frac{3}{y – 3} < 3\) ?

(A) y > 4
(B) y > 12
(C) y < –1
(D) y < 3
(E) y < 3 or y > 4




Are You Up For the Challenge: 700 Level Questions
What worked for me was assuming two cases one where denominator remains positive i.e, y>4 which give me y>4 & the other set where i flip the sign assuming y<3 which gives y<4 SO y<3....... 4<y & y<3 is the answer
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