It is currently 23 Oct 2017, 01:00

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Formula for divisors

Author Message
TAGS:

### Hide Tags

Senior Manager
Joined: 05 Oct 2008
Posts: 270

Kudos [?]: 538 [0], given: 22

### Show Tags

16 May 2010, 01:56
I got the following from m01. Can someone explain how 2*3*2 is derived?
Thanks.

The following formula can be used to find the number of divisors of any given number. Factor 90 ( $$90= 2*3^2*5$$ ) and then multiply the powers+1 $$2*3*2=12$$ . Therefore, divisors of 90 = 12

Kudos [?]: 538 [0], given: 22

Senior Manager
Affiliations: SPG
Joined: 15 Nov 2006
Posts: 320

Kudos [?]: 874 [1], given: 28

### Show Tags

16 May 2010, 02:25
1
KUDOS
ok this is how i see it

power of 2 = 1 --> we add +1 to it --> 2
power of 3 = 2 --> we add +1 to it --> 3
power of 5 = 1 --> we add +1 to it --> 2

So we multiply all of them --> 2.3.2 = 12

And this gives us the number of factors of of 90

Kudos [?]: 874 [1], given: 28

Re: Formula for divisors   [#permalink] 16 May 2010, 02:25
Display posts from previous: Sort by