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26 Jul 2019, 00:26
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E
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Four pool balls—A, B, C, D—are randomly arranged in a straight line. What is the probability that the order will actually be A, B, C, D ?
(A) 1/2
(B) 1/4
(C) 1/6
(D) 1/8
(E) 1/24
(A) 1/2
(B) 1/4
(C) 1/6
(D) 1/8
(E) 1/24
Updated on: 26 Jul 2019, 12:51
Originally posted by Mohammadmo on 26 Jul 2019, 00:30.
Last edited by Mohammadmo on 26 Jul 2019, 12:51, edited 1 time in total.
Last edited by Mohammadmo on 26 Jul 2019, 12:51, edited 1 time in total.
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We've got 24 ways to arrange these letters next each other.
4!= 4×3×2×1=24
one of these ways is exactly, ABCD
so , option (E)
Posted from my mobile device
4!= 4×3×2×1=24
one of these ways is exactly, ABCD
so , option (E)
Posted from my mobile device
26 Jul 2019, 07:17
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Bunuel
Four pool balls—A, B, C, D—are randomly arranged in a straight line. What is the probability that the order will actually be A, B, C, D ?
(D) 1/2
(A) 1/4
(E) 1/6
(B) 1/8
(C) 1/24
(D) 1/2
(A) 1/4
(E) 1/6
(B) 1/8
(C) 1/24
Bunuel please check options sequence is shuffled
total ways ; 4! ; 24
so 1/24
IMO C or E as per pattern
