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09 Apr 2017, 05:40
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C
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Four supporting beams (north, east, south, and west) are holding up a house with a weight distribution in the ratios 11:9:23:7, respectively. There is no other support for the house. If the eastern beam is holding 6300 pounds, what is the total weight of the house?
A. 3500
B. 31500
C. 35000
D. 315000
E. 378000
A. 3500
B. 31500
C. 35000
D. 315000
E. 378000
divyamurali
Joined: 07 Nov 2016
Last visit: 06 Sep 2022
Posts: 6
Own Kudos:
Given Kudos: 33
Location: India
Schools: Great Lakes '19 (A)
GMAT 1: 620 Q47 V29
GPA: 3.9
09 Apr 2017, 06:29
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11:9:23:7 = 11+9+23+7=50
(9/50)*x=6300
X=35000
(9/50)*x=6300
X=35000
09 Apr 2017, 07:54
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Bunuel
Four supporting beams (north, east, south, and west) are holding up a house with a weight distribution in the ratios 11:9:23:7, respectively. There is no other support for the house. If the eastern beam is holding 6300 pounds, what is the total weight of the house?
A. 3500
B. 31500
C. 35000
D. 315000
E. 378000
A. 3500
B. 31500
C. 35000
D. 315000
E. 378000
Weight held by the Eastern beam = (9/50)*total weight = 6300
Hence the total weight = 700*50 = 35000 pounds.
Correct Answer: C
