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Ravi05885
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Fraction [#permalink] New post   15 Mar 2020, 05:25
Can someone help me with the attache problem

new ration = 1.5x/ 1.2Y =?
=5x/4y=?
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Re: Fraction [#permalink] New post   15 Mar 2020, 07:25
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1.5x/1.2y = (3/2x)/(6/5y)= (3/2x)•(5/6y) = 5x/4y. Got it?
Ravi05885 wrote:
Can someone help me with the attache problem

new ration = 1.5x/ 1.2Y =?
=5x/4y=?


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Re: Fraction [#permalink] New post   15 Mar 2020, 08:31
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Ravi05885 wrote:
Can someone help me with the attache problem

new ration = 1.5x/ 1.2Y =?
=5x/4y=?


Hi Ravi05885

\(\frac{1.5x}{1.2y}\)
Multiply both numerator & denominator by 10
= \(\frac{1.5x*10}{1.2y*10}\)
= \(\frac{15x}{12y}\)
= \(\frac{5x}{4y}\)
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Re: Fraction [#permalink] New post   15 Mar 2020, 08:47
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Ravi05885 wrote:
Can someone help me with the attache problem

new ration = 1.5x/ 1.2Y =?
=5x/4y=?


1.5x/ 1.2Y = .3*5x/.3*4y = 5x/4y
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Re: Fraction [#permalink] New post   20 Mar 2020, 04:29
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Ravi05885 wrote:
Can someone help me with the attache problem

new ration = 1.5x/ 1.2Y =?
=5x/4y=?


Solution:

Recall that 1.5 = 15/10 and 1.2 = 12/10. Rewriting, we obtain:

1.5x/1.2y = (15x/10) / (12y/10)

To divide two fractions, we multiply the dividend with the reciprocal of the divisor; thus we obtain:

(15x/10)/(12y/10) = (15x/10)*(10/12y) = 15x/12y = 5x/4y

Alternate Solution:

First, multiply the numerator and the denominator by 10:

1.5x / 1.2 y

15x / 12y

Now reduce the fraction by dividing top and bottom by 3:

5x / 4y
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Re: Fraction [#permalink]
20 Mar 2020, 04:29

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