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From a drawer containing black, blue and gray solid-color

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From a drawer containing black, blue and gray solid-color [#permalink]

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From a drawer containing black, blue and gray solid-color socks, including at least three socks of each color, how many matched pairs can be removed?

(1) The drawer contains 11 socks.

(2) The drawer contains an equal number of black and gray socks.
[Reveal] Spoiler: OA

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Re: From a drawer containing black, blue and gray solid-color [#permalink]

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New post 23 Dec 2009, 10:32
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IMO E
s1) possiblities are
blue=5;black=3,grey=3
blue=3,black=4;grey=4
like this there are more possiblities and no ways differ

s2) as said above

s1)+s2) 5,3,3 or 3,4,4 no. of ways differ
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Re: From a drawer containing black, blue and gray solid-color [#permalink]

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New post 15 Feb 2012, 21:40
IMO E. sock pairs are still uncertain
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Re: From a drawer containing black, blue and gray solid-color [#permalink]

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New post 16 Feb 2012, 00:36
The correct answer is E as there are multiple possibilities for statement A and B.
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Re: From a drawer containing black, blue and gray solid-color [#permalink]

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New post 17 Feb 2012, 20:07
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The answer has to be E.

We know there are "ATLEAST" 3 socks for each color. We do not know the actual number of socks for each of the colors so therefore there is no way to find out. Socks could be more than \(100[/] even!

Statement A: There are a total of [m]11\) socks and we know that there are at least \(3\) socks of each color. Lets try and distribute these:

Possibility \(A\)
Blue \(=5\)
Black \(=3\)
Grey \(=3\)
So matched pairs that can be removed \(=4\)

Possibility \(B\)
Blue \(=3\)
Black \(=4\)
Grey \(=4\)
So matched pairs that can be removed \(=5\)

Since there are Two different answers, this statement alone is insufficient.

Statement B: The drawer contains an equal number of Black and Grey socks.

Multiple possibilities. If you revert back to the solution provided for Statement A, in both those possibilities, the number of Black and Grey socks is equal and we have two different answers. This should also answer your concern as to why both statements together are also insufficient to answer the question.

Hence E should be the correct answer.
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Re: From a drawer containing black, blue and gray solid-color [#permalink]

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New post 17 Feb 2012, 20:47
+1 E....
I'm not good with probability but the probability of the outcome can change when the number of black, Blue or grey socks changes

You can have only 1 Blue 1 Black & the rest grey for example
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Re: From a drawer containing black, blue and gray solid-color [#permalink]

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New post 05 Jun 2016, 13:25
Hello from the GMAT Club BumpBot!

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Re: From a drawer containing black, blue and gray solid-color [#permalink]

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New post 05 Jun 2016, 14:20
msunny wrote:
From a drawer containing black, blue and gray solid-color socks, including at least three socks of each color, how many matched pairs can be removed?

(1) The drawer contains 11 socks.

(2) The drawer contains an equal number of black and gray socks.


If we know exactly how many socks of each color are present, then we can tell the possibility of removing matching pair.

(1) The drawer contains 11 socks.

Possibilities:-
Blue- 3/4/5
Black- 3/4/5
Grey- 3/4/5

Not sufficient.

(2) The drawer contains an equal number of black and gray socks.
Possibilities:-

Blue + black + grey= 3+5+3

Blue + black + grey= 4+3+4

Not sufficient

Statement 1 and 2 together do not give exact number of socks for each color.

E is the answer
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Re: From a drawer containing black, blue and gray solid-color [#permalink]

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New post 06 Aug 2017, 10:04
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: From a drawer containing black, blue and gray solid-color   [#permalink] 06 Aug 2017, 10:04
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