Bunuel wrote:

From the even numbers between 1 and 9, two different numbers are to be chosen at random. What is the probability that their sum will be 8 ?

A. 1/6

B. 3/16

C. 1/4

D. 1/3

E. 1/2

The even numbers between 1 and 9 are 2, 4, 6 and 8. So there are 4 even numbers, and we want to choose two of them. The number of ways to do that is 4C2 = (4 x 3)/2 = 6.

The only way to get a sum of 8 from two different numbers is by picking 2 and 6.

We see that the number of favorable outcomes is 1 and the total number of outcomes is 6. Thus, the probability is 1/6.

Answer: A

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