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olivite
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Functions Updated on: 08 Jul 2011, 09:12
Originally posted by olivite on 07 Jul 2011, 18:49.
Last edited by olivite on 08 Jul 2011, 09:12, edited 1 time in total.
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20% (00:25) correct 80% (00:47) wrong based on 5 sessions

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Try this:
IF f(x)=(x-1)^2, What is the value of f(x-1)?

I have the answer, but i just don't get it.



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olivite
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Functions 07 Jul 2011, 18:54
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Forgot to post the answer choices:

A) x^2+2x+1
B) x^2-4x+2
C) x^2-4x+4
D) x^2+4x+4
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olivite
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Functions 07 Jul 2011, 18:57
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So approached it as follows:
f(x-1)=(x-1)^2-1=x^2-2x+1-1=x^2-2x
Now obviosly it is wrong, because i can't get to any answer choices - i just don't understand why my approach is wrong.
Thank you!
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Functions 07 Jul 2011, 21:50
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olivite
Try this:
IF f(x)=(x+1)^2, What is the value of f(x-1)?

I have the answer, but i just don't get it.
Show more

There is something wrong here.

Given \(f(x) = ([highlight]x[/highlight]+1)^2\)
If you want to find the value of f(x-1), in place of x, you just substitute (x-1).
So \(f(x-1) = ([highlight]x-1[/highlight]+1)^2 = x^2\)
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olivite
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Functions 08 Jul 2011, 09:16
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Yes, you were correct. It was supposed to be f(x)=(x-1)^2
I tend to mix up what & where i need to substitute. All the x's look the same to me :)
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pike
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Functions 08 Jul 2011, 20:47
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\(f(x) = (x-1)^2\)

\(f(x-1) = ((x-1)-1)^2 = (x-2)^2\)

\((x-2)(x-2) = x^2 - 4x +4\)



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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Thank you for understanding, and happy exploring!
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