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# geometry

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Joined: 23 Sep 2016
Posts: 222

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13 Mar 2018, 23:06
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Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 1 sessions

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In the figure shown, if the side of the square is 40, What is the radius of the circle?
A.10(\sqrt{2}-1)
B.20(\sqrt{2}-1)
C.20(\sqrt{2}-1)\frac{(\sqrt{2[}{square_root]+1)}
D.40([square_root]2}-1)
E.40(\sqrt{2}-1)\frac{([square_root]2[}{square_root]+1)}

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Math Expert
Joined: 02 Sep 2009
Posts: 55681

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13 Mar 2018, 23:15
rishabhmishra wrote:
In the figure shown, if the side of the square is 40, What is the radius of the circle?
A.10(\sqrt{2}-1)
B.20(\sqrt{2}-1)
C.20(\sqrt{2}-1)\frac{(\sqrt{2[}{square_root]+1)}
D.40([square_root]2}-1)
E.40(\sqrt{2}-1)\frac{([square_root]2[}{square_root]+1)}

-----------------------------------------------------------------------------------------------

If you like my question then Just press KUDOS button i will keep up with my work and some of the right anwser will receive kudos as a reward
SOURCE:- GLOBALEXPERTS

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This discussion does not meet community quality standards. It has been retired.

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Re: geometry   [#permalink] 13 Mar 2018, 23:15
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