Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 2711:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors
Apr 2610:00 AM EDT
-11:00 AM EDT
The Target Test Prep course represents a quantum leap forward in GMAT preparation, a radical reinterpretation of the way that students should study. Try before you buy with a 5-day, full-access trial of the course for FREE!
Apr 2808:00 AM PDT
-11:00 AM PDT
Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
08 Jul 2019, 14:09
Kudos
Bookmarks
Hello everyone!
Sorry if i posted this topic in incorrect branch.
So, i understood that i had to calculate the are of the given triangle from using different bases and heights.
1. Area = 1/2*12*3=18
2. Area = 1/2*x*7=12 which yields x=36/7
BUT
I see here a quadrilateral ABCD (as i shown on the picture, which is rectangle as we have two opposite right angles there) and, according to that, x should be equal to 3.
Please, help me to stop seeing here a rectangle. Explain, why it is NOT a rectangle.
Thanks in advance and have a nice day!
Sorry if i posted this topic in incorrect branch.
So, i understood that i had to calculate the are of the given triangle from using different bases and heights.
1. Area = 1/2*12*3=18
2. Area = 1/2*x*7=12 which yields x=36/7
BUT
I see here a quadrilateral ABCD (as i shown on the picture, which is rectangle as we have two opposite right angles there) and, according to that, x should be equal to 3.
Please, help me to stop seeing here a rectangle. Explain, why it is NOT a rectangle.
Thanks in advance and have a nice day!
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
Attachments
.PNG [ 12.84 KiB | Viewed 1248 times ]
08 Jul 2019, 14:56
Kudos
Bookmarks
1. CB(3) is not equal to AD(36/7). {opposite sides are not equal}
2. Angle CBA is equals to \(π-cos^{-1}(3/7)\), hence all angles of given quadrilateral are not equal to 90*, and CB is not parallel to AD.
2. Angle CBA is equals to \(π-cos^{-1}(3/7)\), hence all angles of given quadrilateral are not equal to 90*, and CB is not parallel to AD.
plk
08 Jul 2019, 15:04
Kudos
Bookmarks
Yes, i was mistaken suggesting that if two opposite sides of the quadrilateral are equal to 90 it defenetely should be a rectangle. (I tried to draw it but wasn't able to do. Tried after pause and did it successfully)
Sorry for being a bit stupid : )
Sorry for being a bit stupid : )
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
