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# Geometry kills me. I was doing so well until I hit this...

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CEO
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Geometry kills me. I was doing so well until I hit this...  [#permalink]

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13 May 2008, 22:25
00:00

Difficulty:

(N/A)

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0% (00:00) correct 0% (00:00) wrong based on 0 sessions

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Geometry kills me. I was doing so well until I hit this...

Please note D is not the OA - rather it is my random guess after scratching my head for 5 mts.
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Math-q12.JPG [ 44.7 KiB | Viewed 1024 times ]

Kudos [?]: 667 [0], given: 210

CEO
Joined: 17 Nov 2007
Posts: 3584

Kudos [?]: 4586 [0], given: 360

Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
GMAT 1: 750 Q50 V40
Re: GMATPrep1 - Geometry PS [#permalink]

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13 May 2008, 23:12
A

$$\frac{40}{360}=\frac{x}{18\pi}$$

$$x=2\pi$$
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Kudos [?]: 4586 [0], given: 360

CEO
Joined: 17 May 2007
Posts: 2947

Kudos [?]: 667 [0], given: 210

Re: GMATPrep1 - Geometry PS [#permalink]

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13 May 2008, 23:15
How did you get the two 35 s at angle P. I know one of the 35's is because the two lines are parallel, how did u derive the other one ?

Last edited by bsd_lover on 13 May 2008, 23:15, edited 1 time in total.

Kudos [?]: 667 [0], given: 210

Intern
Joined: 07 May 2008
Posts: 16

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Re: GMATPrep1 - Geometry PS [#permalink]

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13 May 2008, 23:15
the answer will be (A) 2 Pi

Explanation:

L(ARC PO)= 35/360 * 2*Pi*9
=3.5 Pi.

Angle PRO and Angle QPR are same =35 (since Line OR is ll to PQ)

L(ARC PO) = L(ARC QR)=3.5 Pi

L(ARC OPQR)= 180/360 * 2*Pi*9 (Since Arc OPQR forms a semicircle hence theta = 180)
=9 Pi.

hence
L(OPQR) = L(Arc OP)+L(Arc PQ)+L(Arc QR)
L(Arc PQ) = 9 Pi - (3.5 Pi +3.5 Pi)
= 2 Pi

Hence the Option A is correct.

Kudos [?]: 2 [0], given: 0

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Joined: 04 May 2006
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Schools: CBS, Kellogg
Re: GMATPrep1 - Geometry PS [#permalink]

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13 May 2008, 23:42
bsd_lover wrote:
How did you get the two 35 s at angle P. I know one of the 35's is because the two lines are parallel, how did u derive the other one ?

If still not get the point, let me know!
_________________

Kudos [?]: 1399 [0], given: 1

CEO
Joined: 17 Nov 2007
Posts: 3584

Kudos [?]: 4586 [0], given: 360

Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
GMAT 1: 750 Q50 V40
Re: GMATPrep1 - Geometry PS [#permalink]

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13 May 2008, 23:42
bsd_lover wrote:
How did you get the two 35 s at angle P. I know one of the 35's is because the two lines are parallel, how did u derive the other one ?

the other angle is 35 because the triangle PR (center) is isosceles: P(center)=R(center)=radius.
_________________

HOT! GMAT TOOLKIT 2 (iOS) / GMAT TOOLKIT (Android) - The OFFICIAL GMAT CLUB PREP APP, a must-have app especially if you aim at 700+ | PrepGame

Kudos [?]: 4586 [0], given: 360

CEO
Joined: 17 May 2007
Posts: 2947

Kudos [?]: 667 [0], given: 210

Re: GMATPrep1 - Geometry PS [#permalink]

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14 May 2008, 01:00
Yup got it .. thanks walker !!! +1.

Kudos [?]: 667 [0], given: 210

Re: GMATPrep1 - Geometry PS   [#permalink] 14 May 2008, 01:00
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