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Geometry questions from GMAT Prep

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Manager
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Geometry questions from GMAT Prep [#permalink]

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New post 05 Aug 2008, 20:14
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

What am I missing here? I see how (2) works, but I can't seem to get Statement (1).
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Re: Geometry questions from GMAT Prep [#permalink]

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New post 05 Aug 2008, 21:16
miccarlo wrote:
What am I missing here? I see how (2) works, but I can't seem to get Statement (1).

we know bco from stem2, bco=40
bco = cbo=40
180-cbo=abo =140
abo+bao+boa = 180
we kno what abo is, and we know that bao = boa, so we can rewrite it as abo+2*bao=180
so bao=(180-abo)/2= 20 degrees

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Re: Geometry questions from GMAT Prep [#permalink]

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New post 05 Aug 2008, 21:53
Right, I got statement 2, but how do you arrive at the answer from statement 1? :-D
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Kudos [?]: 22 [0], given: 3

Current Student
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Joined: 18 Jun 2008
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Kudos [?]: 59 [0], given: 3

Re: Geometry questions from GMAT Prep [#permalink]

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New post 05 Aug 2008, 22:46
miccarlo wrote:
Right, I got statement 2, but how do you arrive at the answer from statement 1? :-D

oops I misread your orignal question :) Thought you knew 1 but didn't know 2.

For stem1 I ddin't do the calculations, but basically you can get 2 equations with 2 variables.

Set x as one set of angles (bao & boa) and y as another set (cbo & bco), then you'll be able to come up with 2 equations with 2 variables and solve for x & y.
------
added in the equations for ya
the big triangle (aoc) = 180 degrees
180 = x + x + 180 - 2y + y
=> y=2x

the complimentary angle to stem1) = 180 - 60 = 120 degrees
120 = x + 180 - 2y
=> 2y = x+60

combine the 2 we get x = 20

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Re: Geometry questions from GMAT Prep   [#permalink] 05 Aug 2008, 22:46
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