Classic rate problem with an algebraic twist. Work it in terms of Giannis's speed and you get there quickly.
1. Let Giannis's speed = v km/h. Since Giannis runs three times as fast as Dinos, Dinos's speed = v/3 km/h.
2. Time for Giannis to finish 10 km = 10/v hours = 600/v minutes.
3. Time for Dinos to finish 10 km = 10/(v/3) = 30/v hours = 1800/v minutes.
4. Giannis finishes m minutes faster, so 1800/v - 600/v = m. That gives 1200/v = m, so v = 1200/m.
Answer: E.
The trap here is picking B (600/m). A lot of people plug Giannis's time alone into the equation instead of the time difference. "600/v = m" feels right when you're moving fast, but m is the gap between the two runners, not Giannis's finishing time.
Also: "three times as fast" means Dinos's speed is v/3, not 3v. Giannis is the fast one. I've seen people flip this and end up with nonsense.