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25 Sep 2019, 00:55
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
67% (01:39) correct
33%
(01:46)
wrong
based on 162
sessions
History
Date
Time
Result
Not Attempted Yet
Given a positive integer p, how many integers are greater than \(2p\) and less than \(4p − 1\)?
A. \(\frac{p}{2}\)
B. \(p\)
C. \(p+1\)
D. \(2p-2\)
E. \(3p-3\)
A. \(\frac{p}{2}\)
B. \(p\)
C. \(p+1\)
D. \(2p-2\)
E. \(3p-3\)
25 Sep 2019, 02:50
Kudos
Bookmarks
Bunuel
Given a positive integer p, how many integers are greater than \(2p\) and less than \(4p − 1\)?
A. \(\frac{p}{2}\)
B. \(p\)
C. \(p+1\)
D. \(2p-2\)
E. \(3p-3\)
A. \(\frac{p}{2}\)
B. \(p\)
C. \(p+1\)
D. \(2p-2\)
E. \(3p-3\)
Number of integers are greater than \(2p\) and less than \(4p − 1\) are {2p+1, 2p+2, 2p + 3, . . . . . . . 4p-2}
The above is an AP series,
--> Last term = a + (n - 1)d
--> 4p - 2 = 2p + 1 + (n - 1)1
--> 4p - 2 = 2p + n
--> n = 2p - 2
IMO Option D
Pls Hit kudos if you like the solution
General Discussion
25 Sep 2019, 00:55
Kudos
Bookmarks
Bunuel
Given a positive integer p, how many integers are greater than \(2p\) and less than \(4p − 1\)?
A. \(\frac{p}{2}\)
B. \(p\)
C. \(p+1\)
D. \(2p-2\)
E. \(3p-3\)
A. \(\frac{p}{2}\)
B. \(p\)
C. \(p+1\)
D. \(2p-2\)
E. \(3p-3\)
Similar question: https://gmatclub.com/forum/given-a-posi ... 65189.html
