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#### Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.  # Given p=|q| and q=3^a-(27^40+27^8), which of the following values of '

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Director  D
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Joined: 01 Oct 2017
Posts: 995
WE: Supply Chain Management (Energy and Utilities)
Given p=|q| and q=3^a-(27^40+27^8), which of the following values of '  [#permalink]

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Question Stats: 73% (02:18) correct 27% (02:30) wrong based on 249 sessions

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Given p=|q| and $$q=3^a-(27^{40}+27^8)$$, which of the following values of 'a' yields the least value for p ?

(A) 120
(B) 140
(C) 180
(D) 185
(E) 190
Math Expert V
Joined: 02 Aug 2009
Posts: 8202
Re: Given p=|q| and q=3^a-(27^40+27^8), which of the following values of '  [#permalink]

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PKN wrote:
Given p=|q| and $$q=3^a-(27^{40}+27^8)$$, which of the following values of 'a' yields the least value for p ?

(A) 120
(B) 140
(C) 180
(D) 185
(E) 190

since p is always positive and p = |q|, we have to find the least |q|
now $$q=3^a-(27^{40}+27^8)=3^a-27^8(27^{32}+1)=3^a-27^8(27^{32}=3^a-27^{40}=3^a-3^{120}$$,
so a ~ 120

A
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Re: Given p=|q| and q=3^a-(27^40+27^8), which of the following values of '  [#permalink]

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chetan2u wrote:
PKN wrote:
Given p=|q| and $$q=3^a-(27^{40}+27^8)$$, which of the following values of 'a' yields the least value for p ?

(A) 120
(B) 140
(C) 180
(D) 185
(E) 190

since p is always positive and p = |q|, we have to find the least |q|
now $$q=3^a-(27^{40}+27^8)=3^a-27^8(27^{32}+1)=3^a-27^8(27^{32}=3^a-27^{40}=3^a-3^{120}$$,
so a ~ 120

A

what happened to the +1 after the 27^{32}?
Math Expert V
Joined: 02 Aug 2009
Posts: 8202
Re: Given p=|q| and q=3^a-(27^40+27^8), which of the following values of '  [#permalink]

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nati1516 wrote:
chetan2u wrote:
PKN wrote:
Given p=|q| and $$q=3^a-(27^{40}+27^8)$$, which of the following values of 'a' yields the least value for p ?

(A) 120
(B) 140
(C) 180
(D) 185
(E) 190

since p is always positive and p = |q|, we have to find the least |q|
now $$q=3^a-(27^{40}+27^8)=3^a-27^8(27^{32}+1)=3^a-27^8(27^{32}=3^a-27^{40}=3^a-3^{120}$$,
so a ~ 120

A

what happened to the +1 after the 27^{32}?

Hi....
Since 1 is very very small as compared to 27^{32}, we can discard 1 as we are looking at an approximate value
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Re: Given p=|q| and q=3^a-(27^40+27^8), which of the following values of '  [#permalink]

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Hi,

I think it could also be solved in the following way:
q=3^a−(27^40+27^8)=3^a- ((3^3)^40 + (3^3)^8

= 3^a - (3^120 + 3^24)

= 3^a - 3^120 - 3^24

if a = 120 then the result would be - 3^24. For all other values, it will be greater than this.

IIMA, IIMC School Moderator V
Joined: 04 Sep 2016
Posts: 1371
Location: India
WE: Engineering (Other)
Given p=|q| and q=3^a-(27^40+27^8), which of the following values of '  [#permalink]

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Bunuel pushpitkc Bunuel niks18 gmatbusters KarishmaB

I have a small query regarding the penultimate step by chetan2u as below:
Quote:
$$3^a-3^{120}$$,
so a ~ 120

Here is the question stem again which asks for a definite value and not approximation.

Quote:
Given p=|q| and $$q=3^a-(27^{40}+27^8)$$, which of the following values of 'a' yields the least value for p ?

I believe chetan2u took the highlighted text to infer that $$3^a$$ must be a positive value.

What I did not get was: if a is actually equal to 120 then the final value of q will be 0 and p will be 0 , which voilates Q stem.
Can you suggest why we did not take next positive value i.e. 140 as correct OA?
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Joined: 27 Oct 2017
Posts: 1274
Location: India
GPA: 3.64
WE: Business Development (Energy and Utilities)
Re: Given p=|q| and q=3^a-(27^40+27^8), which of the following values of '  [#permalink]

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1
Hi

Query1:

I believe chetan2u took the highlighted text to infer that $$3^a$$ must be a positive value.. it is not to be inferred from the question stem.

3^a is always positive- 3^a can never be negative and 3^a tends to zero only if a approaches negative infinity.

Concept: (positive)^x, is always positive, it can not be negative. (positive)^x tends to zero only if a approaches negative infinity.

Query2: if a is actually equal to 120 then the final value of q will be 0 and p will be 0 , which violates Q stem
I am afraid, I couldn't understand this point. How it violates the Question stem.- please explain the query further to let me expand.

In fact , p=|q|. Hence the minimum value of p can be equal to zero.( it cannot be negative). So , as explained in above posts, p approaches zero, when a is 120. (out of the given 5 options).

gmatbusters

I have a small query regarding the penultimate step by chetan2u as below:
Quote:
$$3^a-3^{120}$$,
so a ~ 120

Here is the question stem again which asks for a definite value and not approximation.

Quote:
Given p=|q| and $$q=3^a-(27^{40}+27^8)$$, which of the following values of 'a' yields the least value for p ?

I believe chetan2u took the highlighted text to infer that $$3^a$$ must be a positive value.

What I did not get was: if a is actually equal to 120 then the final value of q will be 0 and p will be 0 , which voilates Q stem.
Can you suggest why we did not take next positive value i.e. 140 as correct OA?

_________________
Director  D
Status: Learning stage
Joined: 01 Oct 2017
Posts: 995
WE: Supply Chain Management (Energy and Utilities)
Given p=|q| and q=3^a-(27^40+27^8), which of the following values of '  [#permalink]

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1
Bunuel pushpitkc Bunuel niks18 gmatbusters KarishmaB

I have a small query regarding the penultimate step by chetan2u as below:
Quote:
$$3^a-3^{120}$$,
so a ~ 120

Here is the question stem again which asks for a definite value and not approximation.

Quote:
Given p=|q| and $$q=3^a-(27^{40}+27^8)$$, which of the following values of 'a' yields the least value for p ?

I believe chetan2u took the highlighted text to infer that $$3^a$$ must be a positive value.

What I did not get was: if a is actually equal to 120 then the final value of q will be 0 and p will be 0 , which violates Q stem.
Can you suggest why we did not take next positive value i.e. 140 as correct OA?

As you know, |q|=q when q>0
|q|=-q when q<0
So, p=|q|=positive
Hence, determining the least value of 'p' is same as determining the least value(minimum) of q.

Given $$q=3^a-(27^{40}+27^8)=3^a-(3^{120}-3^{24})=3^a-3^{120}-3^{24}$$--------------(1)

What I did not get was: if a is actually equal to 120 then the final value of q will be 0 and p will be 0 , which violates Q stem.

when a=120, $$q=3^{120}-3^{120}+3^{24}$$=$$-{3^{24}}\neq0$$

Quote:
$$3^a-3^{120}$$,
so a ~ 120
Here is the question stem again which asks for a definite value and not approximation.

Here a=120 is not approximated. When a=120, the given expression has the least value of q, i.e. $$-3^{24}$$. So, $$p=|q|=-q=-(-3^{24})=3^{24}$$

Quote:
Can you suggest why we did not take next positive value i.e. 140 as correct OA?

Let's take a=140, so (1) becomes, $$q=3^{140}-3^{120}-3^{24}$$. As $$3^{140}-3^{120}$$is positive, so $$|q|> 3^{24}$$
But we want the least value. Therefore, we have to discard a=140.

Quote:
I believe chetan2u took the highlighted text to infer that $$3^a$$ must be a positive value.Given p=|q| and $$q=3^a-(27^{40}+27^8)$$, which of the following values of 'a' yields the least value for p ?

No, the highlighted portion signifies 'p' must be positive. (q<0 (say -5) implies p=|q|=-q=-(-5)=positive; q>0 implies p=|q|=positive)

P.S:- We can have value of the expression(|q|) less than $$3^{24}$$ but we are told to determine the least value of 'p' from the given 5 answer options.(a=120, 140,180,185, and 190)
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Math Expert V
Joined: 02 Aug 2009
Posts: 8202
Re: Given p=|q| and q=3^a-(27^40+27^8), which of the following values of '  [#permalink]

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Bunuel pushpitkc Bunuel niks18 gmatbusters KarishmaB

I have a small query regarding the penultimate step by chetan2u as below:
Quote:
$$3^a-3^{120}$$,
so a ~ 120

Here is the question stem again which asks for a definite value and not approximation.

Quote:
Given p=|q| and $$q=3^a-(27^{40}+27^8)$$, which of the following values of 'a' yields the least value for p ?

I believe chetan2u took the highlighted text to infer that $$3^a$$ must be a positive value.

What I did not get was: if a is actually equal to 120 then the final value of q will be 0 and p will be 0 , which voilates Q stem.
Can you suggest why we did not take next positive value i.e. 140 as correct OA?

Most of the points have been made amply clear in above posts. However, the point on approximation..
What is the least value of p, it is 0 as p=|q|
And at a=120, it is not 0, it is 3^120-(3^120+3^24)=-3^24
So p =|-3^24|=3^24

So that is not equal to 0..
But are we looking for 'a' to get the least value of p...NO then a will be 120.xyz, something in decimals.
We are looking for the least value for the FOLLOWING values
_________________ Re: Given p=|q| and q=3^a-(27^40+27^8), which of the following values of '   [#permalink] 28 Jul 2018, 03:45
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# Given p=|q| and q=3^a-(27^40+27^8), which of the following values of '  