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23 Dec 2020, 07:30
Kudos
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
94% (01:21) correct
6%
(01:55)
wrong
based on 35
sessions
History
Date
Time
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Not Attempted Yet
Given that l1 is parallel to l2 in the figure below, then the value of x° + y° = ?
(A) 90° + x°
(B) 120° – y°
(C) 180° – z°
(D) 210°
(E) 270°
2020-12-21_17-03-24.png [ 13.27 KiB | Viewed 1947 times ]
(A) 90° + x°
(B) 120° – y°
(C) 180° – z°
(D) 210°
(E) 270°
Attachment:
2020-12-21_17-03-24.png [ 13.27 KiB | Viewed 1947 times ]
23 Dec 2020, 07:38
Kudos
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(C). Vertically opposite angles and parrallel lines congruency.
23 Dec 2020, 07:48
Kudos
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Construction, extend the line AC, such that it should intersect the line \(l_2\) at a point (let say) \(P\).
Then, \(\angle CPl_2 = x^{\circ}\)
and, \(\angle DCP = y^{\circ}\)
Therefore, \(x^{\circ}+y^{\circ}+z^{\circ}=180^{\circ}\)
\(x^{\circ}+y^{\circ}=180^{\circ}-z^{\circ}\)
IMO Ans C
Then, \(\angle CPl_2 = x^{\circ}\)
and, \(\angle DCP = y^{\circ}\)
Therefore, \(x^{\circ}+y^{\circ}+z^{\circ}=180^{\circ}\)
\(x^{\circ}+y^{\circ}=180^{\circ}-z^{\circ}\)
IMO Ans C
