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Given that m and n are integers, is m > n ?

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Given that m and n are integers, is m > n ? [#permalink]

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Given that m and n are integers, is m > n ?

(1) |m| > |n|^2

(2) |m| < n
[Reveal] Spoiler: OA

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Last edited by Bunuel on 03 Sep 2014, 11:22, edited 1 time in total.
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Re: Given that m and n are integers, is m > n ? [#permalink]

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New post 03 Sep 2014, 11:26
Given that m and n are integers, is m > n ?

(1) |m| > |n|^2. Since |n|^2 = n^2, then we have that |m| > n^2. If m = 1 and n = 0, then the answer to the question is YES but if m = -1 and n = 0, then the answer is NO. Not sufficient.

(2) |m| < n --> -n < m < n, so m > n is not true. Sufficient.
Or: the absolute value of m is less than n, how can m itself be greater than n? It cannot.

Answer: B.
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Re: Given that m and n are integers, is m > n ? [#permalink]

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New post 15 Aug 2017, 06:45
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Re: Given that m and n are integers, is m > n ?   [#permalink] 15 Aug 2017, 06:45
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