Rashed12 wrote:
Given that there are two boats X and Y which start at the same point. If boat X travels due north at a rate 3 miles/hr and boat Y travels due east at a rate of 4 miles/hr,then at what time will the two boats be 10 miles apart?
A. 1
B. 2
C. 3
D. 4
E. 5
Pls give me +1 kudos.
Now, the two boats are moving perpendicular to each other. So, when we join their paths and the locations, we will get a right angled triangle. That is the start point and the point when they are 10 Kms apart will make a right angled triangle.
Let the time taken be X, so the legs of this triangle are 3x and 4x, and the hypotenuse of this triangle will be 10.
Therefore, with sides 3x and 4x we are looking at 3:4:5 triangle..
Sides 3:4:5 with ratio X = 3x:4x:5x=3x:4x:10
Thus 5x=10...X=2
B
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