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ashutoshsh
Cant we approach it this way..
x=y^2 + z^2 - 2yz\(\)
now we now yz is =13 (which also means that neither y nor z is Zero)
so now y^2 and z^2\(\) can be 1 & 13 or -1 & -13 or 13 & -1 .... but there squares will give sme result.

Isn't Option A sufficient itself, while C repeats the fact given in A?

Bunuel - Please help!

For (1) we don't know whether y and z are integers, so yz = 13 does not necessarily means that (y,z) is (+/-1, +/-13), or (+/-13, +/-1)
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oh yes!
@bunuel- Thank you soo much ! :)
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ashutoshsh
Cant we approach it this way..
x=y^2 + z^2 - 2yz\(\)
now we now yz is =13 (which also means that neither y nor z is Zero)
so now y^2 and z^2\(\) can be 1 & 13 or -1 & -13 or 13 & -1 .... but there squares will give sme result.

Isn't Option A sufficient itself, while C repeats the fact given in A?

Bunuel - Please help!

Hi,
statement II is doing more than telling that they are NON_ZERO..
yes xy = 13 itself means x and y are NOT equal to 0..
But the important point it tells us is that x and y are INTEGERS, so x and y can be different combinations of 1 and 13..
otherwise from A, it can be x= 13/4 and y = 4.. and so on
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Given that X = (Y–Z)^2. What is the value of X?

(1) The product of Y and Z is 13
(2) Y and Z are non zero integers.

stmt (1) & stmt (2) aren't sufficient by themselves.
Combining the two, we see that since product of X,Y : XY=13 and X,Y are Non Zero integers.
So X, can take the values +1/-1 & +13/-13.
in any case X= Y^2+Z^2-2YZ.
Thus we can get a precise value for X by combining the 2 equations.
The OA is below. is this approach is okay ?

Given X = (Y − Z)2.

Considering statement 1:
Product of Y and Z is equal to 13
Since there is no condition on Y and Z so possible values of Y and Z can be (−13, −1) or (13,1) or (1,13) or (−1, −13)
(NOTE: They could be fractions as well, e.g. 2 and 13/2, etc.)
As in LHS we have (Y-Z) to the power 2 so (−13, −1) and (−1, −13) will yield same value of X.
Similarly (13,1) and (1,13) will also yield same value of X.

But different fraction values will give same value of expression (Y − Z)2
now since we are not getting unique value of X so statement 1 itself is not sufficient to provide the answer.

Considering statement 2:
As Y and Z are given to be non zero integers so we can have multiple values of Y and Z for which we will have multiple values of X.
With statement 2 alone also we are not getting any unique answer so statement 2 itself also is not sufficient to provide the answer.


Considering statement 1 and 2 both:
Again by considering statement 1 and 2 together it is known that product of Y and Z are given to be 13 where Y and Z are non zero integers
Possible values of Y and Z are (−13,−1) or (13,1) or (1,13) or (−1,−13)

As the required value is (Y-Z) to the power 2, so (−13, −1) and (−1, −13) will yield same value of X.
Similarly (13,1) and (1,13) will also yield same value of X.
Value of X is (−13 + 1)2 = 144 or (13 − 1)2 = 144.

Now since we are getting unique value of X so statement 1 and 2 combined are sufficient to provide the answer.
Answer: C.
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X = (Y–Z)^2. What is the value of X?

(1) Y.Z = 13
Y and Z can be any infinite combination of real numbers that we cannot determine exact value of X
NOT SUFFICIENT

(2) Y and Z are non zero integers.
Y and Z can be any infinite combination of integers that we cannot determine exact value of X
NOT SUFFICIENT

(1) + (2)
Y.Z = 13 and both are non-zero integers. Thus, possible solution sets of (X, Y) are (-13,-1),(-1,-13),(13,1), and (1,13). Nonetheless, all these sets result in singular value of X = (Y–Z)^2 = 144.
SUFFICIENT

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