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03 Jan 2021, 03:32
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Bunuel
Option D.
A) Let the radius be r and side of square be x. According to the option, r^2 + r^2 = (2*sqrt(2))^2.
r = 2. Thus, the shaded region is 4^2 - pi*(2)^2 = 4(4 - pi).
B) Let the side of the square be x. Thus, 4x = 16, x = 4. Thus, the radius of the circle is 2. Thus, the shaded region is 4^2 - pi*(2)^2 = 4(4 - pi).
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