AndreG
Which of the following represents the range for all \(X\) which satisfy \(|1 - X| \lt 1\) ?
(C) 2008 GMAT Club -
m11#16 * (-1, 1)
* (-1, 2)
* (0, 1)
* (0, 2)
* (1, 2)
Answer:
Explanation:
If \(X \ge 1\) , then the inequality turns into \(X - 1 \lt 1\) or \(X \lt 2\) . If \(X \lt 1\) , then the inequality turns into \(1 - X \lt 1\) or \(X \gt 0\) . Combine the intervals to get the answer.
My problem:
|1-2|=1 not smaller than 1 ... ???
\(|1-x|<{1}\) --> key point is \(x=1\) (key points are the values of \(x\) when absolute values equal to zero), thus two ranges to check:
\(x<1\) --> \(|1-x|=1-x\) and \(|1-x|<{1}\) becomes: \(1-x<{1}\) --> \(x>0\);
\(x\geq{1}\) --> \(|1-x|=-1+x\) and \(|1-x|<{1}\) becomes: \(-1+x<{1}\) --> \(x<2\);
So \(|1-x|<{1}\) holds true for \(0<x<2\).
Answer: D.
As for your question: \(x\) can not equal to 2, because \(0<x<2\) means that \(x\) MUST be less than 2 (and more than zero), for ANY \(x\) from this range given inequality will hold true.
I guess (0,2) should be changed to \(0<x<2\) (as well as all other options) to avoid confusion whether 0 and 2 are inclusive in the range.
Hope it helps.