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16 Jul 2024, 07:00
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B
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Difficulty:
45%
(medium)
Question Stats:
79% (02:37) correct
21%
(03:02)
wrong
based on 453
sessions
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A boulangerie's cost for baking croissants is 0.60 euros for each of the first 100 croissants and 0.30 euros for each additional croissant after the first 100. On Sunday, the boulangerie baked and sold n croissants, where n > 100, for 1.5 euros each. If the profit on selling these croissants was 200%, what is the value of n?
A. 125
B. 150
C. 175
D. 200
E. 400
A. 125
B. 150
C. 175
D. 200
E. 400
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16 Jul 2024, 08:30
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Bunuel
GMAT Club Official Explanation:
The cost for producing n croissants, where n > 100, would be:
0.6*100 + 0.3(n - 100) =
= 60 + 0.3n - 30 =
= 30 + 0.3n.
= 60 + 0.3n - 30 =
= 30 + 0.3n.
The profit for selling n croissants, at 1.5 euros each, would be:
Profit = Revenue - Cost =
= 1.5n - (30 + 0.3n) = 1.2n - 30.
= 1.5n - (30 + 0.3n) = 1.2n - 30.
The profit of 200% would imply that:
Profit/Cost = 200/100
(1.2n - 30)/(30 + 0.3n) = 2
1.2n - 30 = 60 + 0.6n
0.6n = 90
n = 150.
(1.2n - 30)/(30 + 0.3n) = 2
1.2n - 30 = 60 + 0.6n
0.6n = 90
n = 150.
Answer: C.
General Discussion
16 Jul 2024, 07:31
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We know:
Cost = 0,6 * 100 + 0,3 * add
Price = 1,5 = 3*cost, because the profit is 200%
n>100
So we set up:
1,5n = 3*[100*0,6 + 0,3 *(n-100)]
1,5n = 3*[6 + 0,3n - 3]
1,5n = 9 + 0,9n
0,6n = 9
n = 150
Answer is B
Cost = 0,6 * 100 + 0,3 * add
Price = 1,5 = 3*cost, because the profit is 200%
n>100
So we set up:
1,5n = 3*[100*0,6 + 0,3 *(n-100)]
1,5n = 3*[6 + 0,3n - 3]
1,5n = 9 + 0,9n
0,6n = 9
n = 150
Answer is B
