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Statement 1 tells us that b is an even integer of the form odd*2, so b can be 2, 6, 10 etc.. Lets say a = 1, then 10^a+b is divisible by 3 when b is 2 but not when b is 6 so insufficient.
Statement 2 tells us that b is less than 10, but then b can be 1,2,3 etc. and divisibility of 10^a+b for these values of b would be different (yes as well as No) so insufficient.
Combining 1 and 2 will give that b can be 2 or 6 but the answer for divisibility is different for 2 and 6, so insufficient once again. Hence answer is E.