Option C - 36
sol
Van carries student =3 v
Bus carries student =14 b
So vb= 3v+14b
Solving for v
v(b-3)=14b
v=14b/b-3 = 14 + 42/b-3
For positive integer b-3 must be divisible by 42
so possible values are = 1,2,3,4,7,14,21
and B>3 and B<15
so values for b can be - 4,5,6,9,10
So if b 4 then b-3= 1 , 42 and v= 56 , V+B= 60
B -5 , B-3 =2 , 42/(b-3)= 21 , v= 40 V+B=40
B is 6 , B-3= 3 , 14 , v= 28 V+B= 34
B is 9 , B-3 =6 , v = 21 V+B =30
B is 10 , B-3 =7 , v=20 V+B=30
We donot have 36 as the value so 36 is the ans
Bunuel
A school used only vans and buses to transport students on a field trip. Each van carried exactly 3 students, and each bus carried exactly 14 students. The number of vans used, when multiplied by the number of buses used, was equal to the total number of students transported. If fewer than 15 buses were used, which of the following could NOT be the total number of vehicles used?
A. 30
B. 34
C. 36
D. 40
E. 60
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