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09 Jul 2026, 07:20
Kudos
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we need integers where : 30 < 1/3^n < 3000
try putting values numbers for n
n=- 3 : 1/3^-3 =27
n= -4 : 1/3^-4 = 81
n= -5 : 1/3^-5 =243
n= -6 : 1/3^-6 = 729
n= -7 : 1/3^-7 = 2187
n= -8 : 1/3^-8 = 6561
values which are betwen 30 and 3000
only : 81,243,729,2187 : this comes from -4,-5,-6,-7
finding median of these numbers :
-6+ (-5)/ 2 = 11/2
Answer: D
try putting values numbers for n
n=- 3 : 1/3^-3 =27
n= -4 : 1/3^-4 = 81
n= -5 : 1/3^-5 =243
n= -6 : 1/3^-6 = 729
n= -7 : 1/3^-7 = 2187
n= -8 : 1/3^-8 = 6561
values which are betwen 30 and 3000
only : 81,243,729,2187 : this comes from -4,-5,-6,-7
finding median of these numbers :
-6+ (-5)/ 2 = 11/2
Answer: D
Quote:
09 Jul 2026, 07:28
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Ans Choice D: If 3000>3^-n>30 ; -8>n>-3
As n is an integer, n=-4,-5,-6 & -7; Median of all values = -11/2
As n is an integer, n=-4,-5,-6 & -7; Median of all values = -11/2
Bunuel
09 Jul 2026, 07:40
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Answer will be -5.5
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09 Jul 2026, 07:57
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From the question we can infer that value of n has to be negative.
If n=-3, the value i of 1/3^n=27
.:Value of n starts from -4
and has to lesser greater than or equal to -6
.: median is -5
If n=-3, the value i of 1/3^n=27
.:Value of n starts from -4
and has to lesser greater than or equal to -6
.: median is -5
Bunuel
