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Ans Choice D: Maria,M painted 25% ; Felix, F painted 50% of rest (75%) = 37.5% and Nora, N painted 37.5%(rest). at thier respective constant hourly rates.
Total time spent = T hrs
Maya spent = T/2 hrs
Nora spent = 2 hrs
Felix spent = (T/2) - 2 hrs
If we can find Maya and Felix individual rates we can find combined rates also
Stmt 1: Felix worked for 4 hrs
T/2 - 2 = 4 ; T = 12hrs
F painted 37.5% in 4 hrs which gives F can complete total in 32/3 hrs
M painted 25% in 6 hrs which gives M can complete total in 24 hrs.
Therefore, combined M+F can be derived. Sufficient.

Stmt 2 : Time M and N spent is twice F spent ; T/2 +2 = 2*(T/2 - 2) ; T=12 hrs and same process like in Stmt2 can be followed. Hence Sufficient.
Bunuel
Maya, Felix, and Nora painted a mural at a community center in consecutive shifts, each at a constant hourly rate. Maya painted the first 25% of the mural, Felix painted the next 50%, and Nora painted the remainder. If Maya’s shift accounted for 50% of the total time spent on the mural and Nora worked for 2 hours, how many hours would it have taken Maya and Felix to complete the entire mural if they had worked together from start to finish at their same respective constant rates?

(1) Felix worked on the mural for 4 hours.
(2) The total time Maya and Nora spent on the mural was twice the time Felix spent on the mural.


 


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Bunuel
Maya, Felix, and Nora painted a mural at a community center in consecutive shifts, each at a constant hourly rate. Maya painted the first 25% of the mural, Felix painted the next 50%, and Nora painted the remainder. If Maya’s shift accounted for 50% of the total time spent on the mural and Nora worked for 2 hours, how many hours would it have taken Maya and Felix to complete the entire mural if they had worked together from start to finish at their same respective constant rates?

(1) Felix worked on the mural for 4 hours.
(2) The total time Maya and Nora spent on the mural was twice the time Felix spent on the mural.


 


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Maya’s rate and work done: M*T/2 = 1/4
Felix’s rate and work done: F*X = 2/4
Nora’s rate and work done: N*2 = 1/4

The question asks us to find the time taken to complete the work if Maya and Felix work together.

1. This gives us Felix’s time (X). From here we can calculate Maya’s time (T=12) and arrive at the combined rate. Sufficient.

2. This gives us a relation between Maya’s, Felix’s, and Nora’s time. From here we can calculate Maya’s and Felix’s time and arrive at the combined rate. Sufficient.

Answer is D.
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t = time to complete the entire mural

M: 1/4 in t/2, rate=1/2t
F: 1/2
N: 1/4 in 2 hours, rate=1/8

(1)
F: 2 hours

t = 4+2+t/2
t = 12

rate of F: (1/2)/4 = 1/8
rate of M: 1/2t = 1/24

together: 1/8+1/24=1/6

time together = 6 hours

Sufficient

(2)
t/2 + 2 + (t/2 + 2)/2 = t
t/2 + 2 = 2t/3
3t + 12 = 4t
t = 12

This is the same info given in st 1, so rates can be calculated too and time together = 6 hours.

Sufficient

The correct answer is D
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Free information:
Maya painted 25%
Felix 50%
Nora 25%

Let the total time be T. Maya took T/2
Nora took 2 hrs
So T= Tm+Tf+Tn
T= T/2+2+Tf

Tf=T-T/2-2
Tf=T/2-2
How much time would Maya and fix take

Find the time and their rates

St1. Tf = 4hr
4=T/2-2
6=T/2
T= 12 hrs

Rate for Maya= 25%/6=1/24
Rate for Felix= 50%/4=1/8
Combined rate = 1/6
So they will take 6 hrs sufficient

St2 Maya + Nora time= 2X Felix time

T/2+2=T(T/2-2)
6=T/2
T=12
We can calculate the rates hence st2 is sufficient too.
So D Answer
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A is sufficent
Bcz we can find time of 1 which is T = 6+T/2 and Rate we know so A is suu And B is not
Bunuel
Maya, Felix, and Nora painted a mural at a community center in consecutive shifts, each at a constant hourly rate. Maya painted the first 25% of the mural, Felix painted the next 50%, and Nora painted the remainder. If Maya’s shift accounted for 50% of the total time spent on the mural and Nora worked for 2 hours, how many hours would it have taken Maya and Felix to complete the entire mural if they had worked together from start to finish at their same respective constant rates?

(1) Felix worked on the mural for 4 hours.
(2) The total time Maya and Nora spent on the mural was twice the time Felix spent on the mural.


 


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My ans is A) Stat 1 is suff

Let total work be 40

WorkRateTime
Maya10x
Felix20y
Nora1052
Total40

We need to find x and y. Time spent by Maya and Felix working together= 40/(x+y)

1) Stat 1, with the given info we can find x and y. Hence sufficient
y= 20/4= 5
x=10/(4+2)= 10/6 (time taken by Maya is 50%= total time taken by Felix and Nora)
2) Stat 2, we cannot find both x and y hence Insufficient
Bunuel
Maya, Felix, and Nora painted a mural at a community center in consecutive shifts, each at a constant hourly rate. Maya painted the first 25% of the mural, Felix painted the next 50%, and Nora painted the remainder. If Maya’s shift accounted for 50% of the total time spent on the mural and Nora worked for 2 hours, how many hours would it have taken Maya and Felix to complete the entire mural if they had worked together from start to finish at their same respective constant rates?

(1) Felix worked on the mural for 4 hours.
(2) The total time Maya and Nora spent on the mural was twice the time Felix spent on the mural.


 


This question was provided by GMAT Club
for the GMAT World Cup Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

 


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