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Answer should be C.

1) B can be two points B1(10, 10) or B2(-10,10)
therefore Sabc is not certain

2) B can be B1(10, 10) or B2(10, -10)
although AC is certain, but the height from B1 to AC and B2 to AC are not the same.
therefore Sabc is not certain

put 1) and 2) together,
B can only be (10, 10)
Sabc can be calculated.
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The answer is D, both pairs of triangles have the same base and height.
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Area = 1/2 * base *height = 1/2*20*h

where h is the length of the perpendicular from (x,y) to x axis.

1. Sufficient

x>=0
=> x=y=10 => (x,y) = (10,10)
x<0
=> -x =y=10 =>(x,y) = (-10,10)

both of the above points result in the height of 10

2. Sufficient

y>=0

x=y=10 => (x,y) = (10,10)

y<0
x=-y=10 => (x,y) = (10,-10)

both of the above points result in the height of 10

Answer is D.
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If vertices of a triangle are A (5, 0), B (x, y) and C (25, 0), what is the area of the triangle?

(1) \(|x| = y = 10\)

The above statement means that \(y\) is 10, but \(x\) can be either -10 or 10. Thus, the third vertex B can be either at (-10, 10) or (10, 10). Notice, however, that the area will be the same in either case. The base of the triangle, the red segment in the image below, will have a length of 20, and the height from B will be 10. Therefore, the area of the triangle will be \(\frac{1}{2}*20*10 = 100\). Sufficient.



(2) \(x = |y| = 10\)

The above statement means that \(x\) is 10, but \(y\) can be either -10 or 10. Thus, the third vertex B can be either at (10, 10) or (10, -10). Notice, however, that the area will be the same in either case. The base of the triangle, the red segment in the image below, will have a length of 20, and the height from B will be 10. Therefore, the area of the triangle will be \(\frac{1}{2}*20*10 = 100\). Sufficient.




Answer: D
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