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21 Jun 2008, 10:13
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Can some one explain the below question? Thanks!
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21 Jun 2008, 11:20
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Let’s denote the cars as 1,2,3. Total number of possible outcomes is 3*3*3 = 27.
Number of favorable outcomes is the number of permutations of a set (1,2,3) which is 3! = 6.
Hence, p=6/27 = 2/9.
Number of favorable outcomes is the number of permutations of a set (1,2,3) which is 3! = 6.
Hence, p=6/27 = 2/9.
21 Jun 2008, 11:36
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another way:
\(p=1*\frac23*\frac13=\frac29\)
\(p=1*\frac23*\frac13=\frac29\)
