It is currently 17 Oct 2017, 12:29

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# GMAT SET 16 - 4

 post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
Manager
Joined: 14 Jan 2006
Posts: 96

Kudos [?]: 40 [0], given: 2

Schools: HKUST
GMAT SET 16 - 4 [#permalink]

### Show Tags

01 Oct 2008, 01:48
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Please solve.
Attachments

untitled.JPG [ 51.33 KiB | Viewed 763 times ]

Kudos [?]: 40 [0], given: 2

Manager
Joined: 30 Sep 2008
Posts: 111

Kudos [?]: 20 [0], given: 0

Re: GMAT SET 16 - 4 [#permalink]

### Show Tags

01 Oct 2008, 08:38
x> 90 <=> a^2 + b^2 < c^2

(1) insufficient, c is unknown
(2) insufficient, a,b are unknown

(1) & (2)

a^2 + b^2 < 15 < 4^2 < c^2
<=> a^2 + b^2 < c^2

Answer: C

Kudos [?]: 20 [0], given: 0

Senior Manager
Joined: 04 Jan 2006
Posts: 276

Kudos [?]: 43 [0], given: 0

Re: GMAT SET 16 - 4 [#permalink]

### Show Tags

01 Oct 2008, 09:14
This is the trigonometry approach. Some people can totally ignore this solution.

c > 4
c^ > 16 ---------- (1)

a^2 + b^2 < 15
-(a^2) - (b^2) > -15 ---------- (2)

Since; $$c^2 = a^2 + b^2 - 2abcos(x)$$
and c^2 > 16

a^2 + b^2 - 2abcos(x) > 16 ---------- (3)
-2abcos(x) > 16 - 15 ---------- (3) + (2)
-2abcos(x) > 1
cos(x) > -1/(2ab)

cos(x) < 0 if and only if 90 < x < 180

Therefore, C is the answer.

Kudos [?]: 43 [0], given: 0

SVP
Joined: 17 Jun 2008
Posts: 1535

Kudos [?]: 279 [0], given: 0

Re: GMAT SET 16 - 4 [#permalink]

### Show Tags

01 Oct 2008, 12:30
What the question is really asking is whether c^2 is more than (a^2 + b^2). In a right angled triangle, c^2 = (a^2 + b^2). However, if the angle is more than 90 degree, the triangle will open up and in order to cover that, c has to be longer than it was for right angled triangle.

C should be the answer.

Kudos [?]: 279 [0], given: 0

Re: GMAT SET 16 - 4   [#permalink] 01 Oct 2008, 12:30
Display posts from previous: Sort by

# GMAT SET 16 - 4

 post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.