Ferihere
dahcrap
The answer is 26 + 26^2 + 26^3
Can you explain or give a source which may provide explanation for this kind of problems, probabilities???
One Letter codes:
@
26 letters = 26 codes
Two Letter codes:
@#
@ can be one of 26 letters. # can be one of 26 letters. It's a permutation. Question specifically mentions that repetitions are allowed (i.e. code: JJ is valid).
as a result we have 26 * 26 choices.
Three letter codes:
same as two letter codes. 26 * 26 * 26
once you add all of them, you get choice E. Of course, as I mentioned above, the best way to save time is that as soon as you realize the solution, you start from the biggest number and go on from there. In this case, whoever does 26^ 3first, saves time by not having to do the other two. This is because 26 ^3 is bigger than all other choices except E.
Also note that if repetitions weren't allowed calcuation would then be: 26 + 26*25 + 26 * 25 * 24
hope this helps.