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GMATPREP-inequality

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VP
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GMATPREP-inequality [#permalink]

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New post 28 Mar 2009, 01:51
00:00
A
B
C
D
E

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(N/A)

Question Stats:

100% (01:23) correct 0% (00:00) wrong based on 0 sessions

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This topic is locked. If you want to discuss this question please re-post it in the respective forum.

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Pls explain the answer
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Re: GMATPREP-inequality [#permalink]

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New post 28 Mar 2009, 04:55
I think it is B.

stmnt 1 - it could be that |x-y|>|x|-|y| or |x-y|=|x|-|y|.
stmn2 - any way you slice it, |x-y| will always be > |x|-|y|, if either x or y <0.

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Re: GMATPREP-inequality [#permalink]

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New post 28 Mar 2009, 06:23
Statement 1 insufficient - You can plug in values and check it out
Let's say y is 1 and x is 2. Then it becomes 1 = 1
Let's say y is -1 and x is 2. Then it becomes 3 > 1

Statement 2 is sufficient - Here again we can plug in values
xy < 0 means either x < 0 or y < 0
for x < 0, x = -1 and y = 2, it is 3 > -1
for y < 0, y = -1 and x = 2, it is 3 > 1

So the answer is B. What is the OA?

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VP
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Re: GMATPREP-inequality [#permalink]

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New post 28 Mar 2009, 21:56
Yes, OA is B.
Do u think in such kind of questions, plugging in the values is the best method?

tharunv wrote:
Statement 1 insufficient - You can plug in values and check it out
Let's say y is 1 and x is 2. Then it becomes 1 = 1
Let's say y is -1 and x is 2. Then it becomes 3 > 1

Statement 2 is sufficient - Here again we can plug in values
xy < 0 means either x < 0 or y < 0
for x < 0, x = -1 and y = 2, it is 3 > -1
for y < 0, y = -1 and x = 2, it is 3 > 1

So the answer is B. What is the OA?

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Re: GMATPREP-inequality   [#permalink] 28 Mar 2009, 21:56
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