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# GMATPrep - Maths

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Senior Manager
Joined: 05 Jun 2008
Posts: 289
GMATPrep - Maths  [#permalink]

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14 Sep 2008, 04:35
pl explain, how the attached can be solved.......

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CEO
Joined: 17 Nov 2007
Posts: 3484
Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
GMAT 1: 750 Q50 V40
Re: GMATPrep - Maths  [#permalink]

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15 Sep 2008, 08:00
4P4=4!=24 - Total number of possible combinations.
4 - the number of possible options for a right enveloper
2 - the number of possible options for a first wrong enveloper
1 - the number of possible options for a second wrong enveloper
4*2=8 - Total number of possible combinations with only 1 right enveloper.

p=8/24=1/3
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Senior Manager
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Re: GMATPrep - Maths  [#permalink]

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15 Sep 2008, 09:59
Thanks, You are amazing walker...

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Re: GMATPrep - Maths &nbs [#permalink] 15 Sep 2008, 09:59
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# GMATPrep - Maths

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