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uvs_mba
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GMATPREP Triangular region 22 Sep 2006, 17:00
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Selected answer may or may not be right :-D



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GMATPREP Triangular region 22 Sep 2006, 21:33
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Side QP is perpendicular to PR, as
QP = PR = 5, and QR = 5sqrt (2) (pythagoras theorem)

Area = 1/2 *base * height
= 1/2 * 5 * 5 = 12.5
(A)
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uvs_mba
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GMATPREP Triangular region 22 Sep 2006, 21:44
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Thanks, the answer is A. I totally missed out on hte rt triangle :oops:

it makes sense now.
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govinam
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GMATPREP Triangular region 23 Sep 2006, 13:31
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How do you determine that it is a right angle?
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GMATPREP Triangular region 24 Sep 2006, 06:25
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If the product of slopes of two lines is -1, then they are perpendicular

Slope of PQ = -3/4

Slope of RP = 4/3

Thus they are perpendicular

Find slope by (y2-y1)/(x2-x1)
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GMATT73
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GMATPREP Triangular region 25 Sep 2006, 08:41
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uvs_mba
Thanks, the answer is A. I totally missed out on hte rt triangle :oops:

it makes sense now.
Show more


Another way to solve this one is to extend four lines to the x and y axis and create four separate triangles. The total area of the rectangle is 28 (7*4)

Then subtract the areas from the three interior triangles. 28-15.5=12.5

(A)

Might not be the fastest way, but it works.
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GMATPREP Triangular region 25 Sep 2006, 09:15
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GMATT73 thats how I got the result



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