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salr15
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GMATPrep: Working together problem 30 Jun 2007, 20:39
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Please explain.



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UMB
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GMATPrep: Working together problem 30 Jun 2007, 21:42
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E.

a) 1/A +1/B=1/(6/5)=5/6

b) 1/A +1/C=1/(3/2)=2/3

c) 1/B+ 1/C= 1/2 SO

a+b+c ====> 2* (1/A+1/B+1/C) =2

1/A+1/B+1/C=1 Go with E
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shmegs
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GMATPrep: Working together problem 02 Jul 2007, 05:03
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UMB,
Could you please explain your reasoning after arriving at the hourly rates? I don't understant how you arrived at 2*(1/A +1/B + 1/c)=2. Thanks.
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trahul4
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GMATPrep: Working together problem 02 Jul 2007, 07:45
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Answer is E.

We can arrive at 3 equations from the data given in the question

1. 1/a + 1/b = 5/6
2. 1/a + 1/c = 2/3
3. 1/b + 1/c = 1/2

now we have 3 distinct equations and 3 unknowm.. solving for a,b,c we can arrive at a=2,b=3 and c= 6

Now if you want to find the total use the formula

1/a + 1/b + 1/c = 1/Total

therefore total = 1
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Andrey2010
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GMATPrep: Working together problem 03 Jul 2007, 08:10
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The same solution but from another side.

A, B, C - rates

(A + B) * 6 / 5 = 1
(A + C) * 3 / 2 = 1
(B + C) * 2 = 1

And at the end we have answer E



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