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30 Jun 2008, 08:48
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30 Jun 2008, 08:53
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(560-Y)*100/(800 - Y) = 60
=> Y = 200
=> Y = 200
30 Jun 2008, 08:55
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The number of these "long term employes" is \(800*70% = 560\)
We want to solve \(\frac{560-y}{800-y} = 60%\) and that gives \(y = 200\)
We want to solve \(\frac{560-y}{800-y} = 60%\) and that gives \(y = 200\)
