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guygmat
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100% (03:44) correct 0% (00:00) wrong based on 4 sessions

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The equation x = 2y2 + 5y - 17, describes a parabola in the xy coordinate plane. If line l, with slope of 3, intersects the parabola in the upper-left quadrant at x = -5, the equation for l is

A)3x + y + 15 = 0
B)y - 3x - 11 = 0
C)-3x + y - 16.5 = 0
D)-2x - y - 7 = 0
E)-3x + y + 13.5 = 0



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fluke
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guygmat
The equation x = 2y2 + 5y - 17, describes a parabola in the xy coordinate plane. If line l, with slope of 3, intersects the parabola in the upper-left quadrant at x = -5, the equation for l is

A)3x + y + 15 = 0
B)y - 3x - 11 = 0
C)-3x + y - 16.5 = 0
D)-2x - y - 7 = 0
E)-3x + y + 13.5 = 0
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guygmat:
Is option "C": -3x + y - 6.5 = 0?
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fluke
guygmat
The equation x = 2y2 + 5y - 17, describes a parabola in the xy coordinate plane. If line l, with slope of 3, intersects the parabola in the upper-left quadrant at x = -5, the equation for l is

A)3x + y + 15 = 0
B)y - 3x - 11 = 0
C)-3x + y - 16.5 = 0
D)-2x - y - 7 = 0
E)-3x + y + 13.5 = 0

guygmat:
Is option "C": -3x + y - 6.5 = 0?
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Hi Fluke ,
How do u solve this ? use vertex of parabola?(-b/2a, c-b^2/4a)?
I tried but im getting a different contant value..not even 6.5

guy gmat: R u sure on the options?
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guygmat
The equation x = 2y2 + 5y - 17, describes a parabola in the xy coordinate plane. If line l, with slope of 3, intersects the parabola in the upper-left quadrant at x = -5, the equation for l is

A)3x + y + 15 = 0
B)y - 3x - 11 = 0
C)-3x + y - 16.5 = 0
D)-2x - y - 7 = 0
E)-3x + y + 13.5 = 0
Show more

Here it is:

\(x=2y^2+5y-17\)

(-5, +y): is one of the solutions of this equation.

\(-5=2y^2+5y-17\)
\(2y^2+5y-12=0\)
\(2y^2+8y-3y-12=0\)
\(2y(y+4)-3(y+4)=0\)
\((2y-3)(y+4)=0\)

y=-4 OR y=3/2

Upper left quadrant has positive y.
y=3/2

Now, what is the equation of line that has a slope of 3 and passes through (-5, 3/2).



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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Thank you for understanding, and happy exploring!
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