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Bunuel
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The cows consume the original field plus any growth rate occurring during the time that they are grazing.

Set g equal the growth rate and r equal the cows eating rate.

1+24G = 70*24*R

1+60G = 30*60*R

Subtracting the top from the bottom:

36G = 120R so G=10R/3

Substituting G back into the first equation:

1+80R = 1680R and R=1/1600. Therefore G = 1/480.

So how many cows are necessary to graze the field fully over 96 days ?

1+96(1/480) = 96*C/1600

(576/480) =96C/1600.

C = (576*1600)/(480*96) = (10*576)/(3*96) =(10*24)/(3*4) = 20 Cows
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