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17 Sep 2010, 04:00
Kudos
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
80% (01:18) correct
20%
(03:16)
wrong
based on 5
sessions
History
Date
Time
Result
Not Attempted Yet
A group of tourists needed to walk 45 miles. During the first day the group walked 19 miles. To complete the requires distence during the secound day. the group had to cover the distance which was approximatly what percent greater than the distance walked during the first day?
a)11%
b)16%
c)27%
d)37%
e)58%
a)11%
b)16%
c)27%
d)37%
e)58%
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17 Sep 2010, 04:04
Kudos
Bookmarks
45 miles
19 miles the first day so 26 miles left
the equation the solve is the following: 26 = 19*(1+x/100)
which lead to x = 700/19 = (approximately) 37 so ANS : D
19 miles the first day so 26 miles left
the equation the solve is the following: 26 = 19*(1+x/100)
which lead to x = 700/19 = (approximately) 37 so ANS : D
17 Sep 2010, 04:08
Kudos
Bookmarks
I had the same explaination in the book ? whats the logic for "the equation the solve is the following: 26 = 19*(1+x/100)"?
