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03 Dec 2017, 01:00
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Difficulty:

55% (hard)

Question Stats:

56% (01:20) correct 44% (01:34) wrong based on 77 sessions

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Greg buys bananas and apples for a total price of $2.45. How many pounds of fruit did Greg buy? (1) The price of each pound of bananas is$0.49

(2) The price of each pound of apples is $0.98 _________________ Math Expert Joined: 02 Aug 2009 Posts: 7764 Re: Greg buys bananas and apples for a total price of$2.45. How many poun  [#permalink]

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03 Dec 2017, 07:42
1
Bunuel wrote:
Greg buys bananas and apples for a total price of $2.45. How many pounds of fruit did Greg buy? (1) The price of each pound of bananas is$0.49

(2) The price of each pound of apples is $0.98 value of both things given, so statement combined can be sufficient But when you look at the similar type of values, look for a trap.. combined.. $$0.49b+0.98a = 2.45.................... 0.49b+2*0.49a = 5*0.49.................... b+2a=5$$ two possiblities b=3,a=1 b=1, a=2 insuff E _________________ Manager Joined: 24 Nov 2016 Posts: 218 Location: United States Re: Greg buys bananas and apples for a total price of$2.45. How many poun  [#permalink]

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03 Dec 2017, 10:15
Bunuel wrote:
Greg buys bananas and apples for a total price of $2.45. How many pounds of fruit did Greg buy? (1) The price of each pound of bananas is$0.49

(2) The price of each pound of apples is $0.98 (1) b = 49$/lbs: not suf.
(2) a = 98 $/lbs: not suf. (3) total price is 245 cents which can be [i] 1 pound of banana + 2 pounds of apples = 49 + 2*98 = 245 cents. Or, [ii] 3 pounds of bananas + 1 pound of apples = 3*49 + 98 = 245 cents; We have two solutions [i] 3 pounds of fruit and [ii] 4 pounds of fruit. not suf. (E) is the answer. Target Test Prep Representative Status: Founder & CEO Affiliations: Target Test Prep Joined: 14 Oct 2015 Posts: 6923 Location: United States (CA) Re: Greg buys bananas and apples for a total price of$2.45. How many poun  [#permalink]

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11 Jan 2018, 15:06
Bunuel wrote:
Greg buys bananas and apples for a total price of $2.45. How many pounds of fruit did Greg buy? (1) The price of each pound of bananas is$0.49

(2) The price of each pound of apples is $0.98 We can let b = the number of pounds of bananas he bought and a = the number of pounds of apples he bought, and we know the total spent is$2.45.

Statement One Alone:

The price of each pound of bananas is $0.49. Since we do not know anything about the price of apples, statement one alone is not sufficient to answer the question. Statement Two Alone: The price of each pound of apples is$0.98.

Since we do not know anything about the price of bananas, statement two alone is not sufficient to answer the question.

Statements One and Two Together:

Using statements one and two, we can create the equation:

0.49b + 0.98a = 2.45

49b + 98a = 245

49(b + 2a) = 245

b + 2a = 5

Since we cannot determine a unique value of a or b (for example, a could be 2 and b could be 1 OR a could be 1 and b could be 3), the statements together are not sufficient.

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Re: Greg buys bananas and apples for a total price of $2.45. How many poun [#permalink] ### Show Tags 15 Jan 2018, 10:08 Bunuel wrote: Greg buys bananas and apples for a total price of$2.45. How many pounds of fruit did Greg buy?

(1) The price of each pound of bananas is $0.49 (2) The price of each pound of apples is$0.98

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.

Since we have 2 variables and 0 equations,C is most likely to be the answer. So, we should consider 1) & 2) first, since we can save time by first checking whether conditions 1) and 2) are sufficient, when taken together.

Let $$a$$ and $$b$$ be the numbers of apples and bananas Greg bought.

$$0.98 a + 0.49 b = 2.45$$
$$98 a + 49 b = 245$$
$$2 a + b = 5$$

Since we have two solutions $$a = 1, b = 4$$ or $$a = 2, b = 1$$, both conditions together are not sufficient.

Normally, in problems which require 2 equations, such as those in which the original conditions include 2 variables, or 3 variables and 1 equation, or 4 variables and 2 equations, each of conditions 1) and 2) provide an additional equation. In these problems, the two key possibilities are that C is the answer (with probability 70%), and E is the answer (with probability 25%). Thus, there is only a 5% chance that A, B or D is the answer. This occurs in common mistake types 3 and 4. Since C (both conditions together are sufficient) is the most likely answer, we save time by first checking whether conditions 1) and 2) are sufficient, when taken together. Obviously, there may be cases in which the answer is A, B, D or E, but if conditions 1) and 2) are NOT sufficient when taken together, the answer must be E.
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"Only $79 for 1 month Online Course" "Free Resources-30 day online access & Diagnostic Test" "Unlimited Access to over 120 free video lessons - try it yourself" Non-Human User Joined: 09 Sep 2013 Posts: 11655 Re: Greg buys bananas and apples for a total price of$2.45. How many poun  [#permalink]

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