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# Hadeeqa can row a boat 10 kilometers per hour in still water. In a riv

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Hadeeqa can row a boat 10 kilometers per hour in still water. In a riv  [#permalink]

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21 Jul 2017, 21:32
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Hadeeqa can row a boat 10 kilometers per hour in still water. In a river where the current is 5 kilometers per hour, it takes her 4 hours longer to row a given distance upstream than to travel the same distance downstream. Find how many kilometers she rows.

A. 20 km
B. 25 km
C. 30 km
D. 40 km
E. 50 km

Source is unknown to me.

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Hasan Mahmud
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Re: Hadeeqa can row a boat 10 kilometers per hour in still water. In a riv  [#permalink]

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21 Jul 2017, 21:46
D.
When the direction is opposite we should subtract the speeds.
Hence his overall speed will be 10-5=5km/hr.
4 hours more than the usual means 4*5=20 km.
Therefore total distance=20*2=40km

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Re: Hadeeqa can row a boat 10 kilometers per hour in still water. In a riv  [#permalink]

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21 Jul 2017, 21:51
1
Given data:
SB(Speed of boat) = 10kmph
SS(Speed of stream) = 5kmph
TU(Time taken to row upstream) - TD(Time taken to row downstream) = 4 =>
TU = TD + 4

Formula used: Distance = Speed*Time taken

Let the time taken to row downstream be x.
Hence, the speed of boat while going upstream(SU) is 10-5 = 5kmph
Similiarly, the speed of the boat while going downstream(SD) is 10+5 = 15kmph

Distance traveled is equal both ways(upstream & downstream)
TU * SU = TD * SD
5(x+4) = 15x
5x + 20 = 15x => 10x = 20 or x = 2

Therefore distance traveled one way is 15*x = 15*2 = 30km(Option C)

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This discussion does not meet community quality standards. It has been retired.

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Re: Hadeeqa can row a boat 10 kilometers per hour in still water. In a riv   [#permalink] 21 Jul 2017, 21:51
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