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Please help me understand HOW to solve this, rather than the answer itself :
If a motorist has driven 1 hour longer on a certain day and at an average rate of 5 miles per hour faster, he would have covered 70 more miles than he actually did. How many more miles would he have covered than he actually did if he had driven 2 hours longer and at an average rate of 10 miles per hour faster on that day?
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Please help me understand HOW to solve this, rather than the answer itself : If a motorist has driven 1 hour longer on a certain day and at an average rate of 5 miles per hour faster, he would have covered 70 more miles than he actually did. How many more miles would he have covered than he actually did if he had driven 2 hours longer and at an average rate of 10 miles per hour faster on that day?
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150 Miles
Consider "x" original time. "x+1" 1hr longer time
Consider "y" original spped. "y+5" 5 miles faster
Now according to problem statement
(x+1) (y+5) = xy + 70
so 5x + y = 65
Now if 2hrs longer and 10 miles faster means total distance=
(x+2) (y+10)
xy + 10x + 2y +20
xy + 2( y +5x) +20
xy + 2(65) +20
xy +150
original distance is xy and this is xy+150 so 150 miles more he covered.
"If a motorist has driven 1 hour longer on a certain day and at an average rate of 5 miles per hour faster, he would have covered 70 more miles than he actually did"
from that motorist actually drives 70-5= 65 miles per hour.
so in 2 hours with 10 miles/hr more i,e (65+10)*2 = 150 miles more he would have driven.
ans 150 miles ..
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.