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Help with a question in combinatorics

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Intern
Intern
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B
Joined: 17 May 2018
Posts: 15
Help with a question in combinatorics  [#permalink]

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New post 28 Sep 2018, 00:20
Hello, would much appreciate help with this kind of question :

there are 3 baskets, each with 5 balls.
in first basket we have 4 black balls, 1 yellow.
in second we have 3 black balls, 2 yellow.
in third we have 2 black , 3 yellow.
we pick one ball from each basket. what is the probability that we get at least one black ball ?

thanks
Manager
Manager
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S
Joined: 23 Nov 2017
Posts: 107
Location: Singapore
Concentration: Strategy, Other
GMAT 1: 660 Q49 V33
Re: Help with a question in combinatorics  [#permalink]

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New post 28 Sep 2018, 00:28
Somnium wrote:
Hello, would much appreciate help with this kind of question :

there are 3 baskets, each with 5 balls.
in first basket we have 4 black balls, 1 yellow.
in second we have 3 black balls, 2 yellow.
in third we have 2 black , 3 yellow.
we pick one ball from each basket. what is the probability that we get at least one black ball ?

thanks



Is the answer 119/125 ?
Director
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Joined: 19 Oct 2013
Posts: 509
Location: Kuwait
GPA: 3.2
WE: Engineering (Real Estate)
GMAT ToolKit User CAT Tests
Re: Help with a question in combinatorics  [#permalink]

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New post 28 Sep 2018, 00:43
Somnium wrote:
Hello, would much appreciate help with this kind of question :

there are 3 baskets, each with 5 balls.
in first basket we have 4 black balls, 1 yellow.
in second we have 3 black balls, 2 yellow.
in third we have 2 black , 3 yellow.
we pick one ball from each basket. what is the probability that we get at least one black ball ?

thanks


Happen to have the answer choices? What is the source for this question?
Intern
Intern
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B
Joined: 17 May 2018
Posts: 15
Help with a question in combinatorics  [#permalink]

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New post 28 Sep 2018, 02:33
in one of official CATs , but unfortunately I don't remember the exact data that was there so I don't know what the answer should be. I changed the stats a bit..
Manhattan Prep Instructor
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Joined: 04 Dec 2015
Posts: 649
GMAT 1: 790 Q51 V49
GRE 1: Q170 V170
Re: Help with a question in combinatorics  [#permalink]

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New post 01 Oct 2018, 11:20
1
Somnium wrote:
Hello, would much appreciate help with this kind of question :

there are 3 baskets, each with 5 balls.
in first basket we have 4 black balls, 1 yellow.
in second we have 3 black balls, 2 yellow.
in third we have 2 black , 3 yellow.
we pick one ball from each basket. what is the probability that we get at least one black ball ?

thanks


If you see language like 'at least one' in a probability problem, this strategy will usually work. Instead of finding the probability of getting one black ball, then two black balls, then three black balls, you can actually just find the probability of getting all yellow balls, and subtract from 1. You can do that because you're basically looking for the probability that anything other than all yellow is what happens. That'll be the 'opposite' of the probability that you get all yellow.

The probability of getting all yellow balls is 1/5 * 2/5 * 3/5 (the product of the probability of getting a yellow ball from each basket). That equals 6/125.

So, the probability of getting at least one black (in other words, NOT getting all yellow) is 1-6/125 or 119/125.
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Re: Help with a question in combinatorics &nbs [#permalink] 01 Oct 2018, 11:20
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Help with a question in combinatorics

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