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Louis14
Joined: 01 Nov 2019
Last visit: 04 Nov 2023
Posts: 251
Own Kudos:
Given Kudos: 472
Schools: NUS MiF "22 (A) LSE MFin "22 (S) HEC MFin "22
GMAT 1: 680 Q48 V34
GPA: 3.56
12 Feb 2020, 09:10
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How do you solve x^2<16, and get -4<x<4?
I can see the reason, but I'm not being able to understand how to reach that answer algebraically.
I can see the reason, but I'm not being able to understand how to reach that answer algebraically.
15 Feb 2020, 09:35
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Louis14
How do you solve \(x^2<16\), and get \(-4<x<4\)?
I can see the reason, but I'm not being able to understand how to reach that answer algebraically.
I can see the reason, but I'm not being able to understand how to reach that answer algebraically.
First notice that, if \(x^2=16\), then \(x = 4\) or \(x = -4\)
From here we need to recognize that, if \(x > 4\), then \(x^2>16\)
Also, if \(x < -4\), then \(x^2>16\)
However, if \(-4 < x < 4\), then \(x^2<16\)
Does that help?
Louis14
Joined: 01 Nov 2019
Last visit: 04 Nov 2023
Posts: 251
Own Kudos:
Given Kudos: 472
Schools: NUS MiF "22 (A) LSE MFin "22 (S) HEC MFin "22
GMAT 1: 680 Q48 V34
GPA: 3.56
15 Feb 2020, 22:39
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Thanks. As you explained, the logic is quite understandable. What I was wondering was to find an algebraic solution to that question. I guess, it’s one of those questions that must be done manually.
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