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How long does it take a particular jet to fly from its base

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Manager
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How long does it take a particular jet to fly from its base  [#permalink]

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New post 20 Jun 2011, 21:10
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How long does it take a particular jet to fly from its base to the Hawaiian Islands?

(1) If the jet’s average speed were 1 1/4 as fast, the flight would take 4 hours.

(2) The jet’s average speed is 500 miles per hour.
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Re: What a DS!! Awesome question  [#permalink]

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New post 20 Jun 2011, 21:38
Stmt 1:

time(t)*speed(s) = dist (d)

According to stmt 1, 4*(s+(5/4)s)=d

4*9s/4 = d => 9s = d

therefore t*s=9s => t=9 , Sufficient

Stmt 2: Insufficient

So A

Nice question guygmat!
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Re: What a DS!! Awesome question  [#permalink]

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New post 20 Jun 2011, 22:27
guygmat wrote:
How long does it take a particular jet to fly from its base to the Hawaiian Islands?

(1) If the jet’s average speed were 1 1/4 as fast, the flight would take 4 hours.

(2) The jet’s average speed is 500 miles per hour.


St:1 tell us if the plane goes 225% of its original speed it will take 4 hrs .
so 100% = 4*225/100 = 4*2.25 = 9

St2: insufficient
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Re: What a DS!! Awesome question  [#permalink]

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New post 20 Jun 2011, 22:56
guygmat wrote:
How long does it take a particular jet to fly from its base to the Hawaiian Islands?

(1) If the jet’s average speed were 1 1/4 as fast, the flight would take 4 hours.

(2) The jet’s average speed is 500 miles per hour.



agree with A...though have a doubt....1 1/4 as fast - this expression means what? - New Avg Speed is 5/4 times the actual Avg Speed or New Avg Speed is [S + (5/4) S] times the actual Avg Speed....I thought it was the 1st case.... :| ...can someone please clarify :oops:
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Re: What a DS!! Awesome question  [#permalink]

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New post 20 Jun 2011, 23:56
kp1811 wrote:
guygmat wrote:
How long does it take a particular jet to fly from its base to the Hawaiian Islands?

(1) If the jet’s average speed were 1 1/4 as fast, the flight would take 4 hours.

(2) The jet’s average speed is 500 miles per hour.



agree with A...though have a doubt....1 1/4 as fast - this expression means what? - New Avg Speed is 5/4 times the actual Avg Speed or New Avg Speed is [S + (5/4) S] times the actual Avg Speed....I thought it was the 1st case.... :| ...can someone please clarify :oops:


It should be the first case; statement 1 can be rephrased as: 'If the jet's speed was 5/4 times the current speed'. It's not '9/4', just as when we say one thing is 'twice as fast' as another, we mean that it is 2 times as fast, not 3 times as fast. I don't know why the question uses a mixed number in the question; the GMAT would always write 5/4 and not 1 1/4 in this kind of question.
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Re: What a DS!! Awesome question  [#permalink]

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New post 21 Jun 2011, 00:09
Let the speed be s, distance d and time t.
s=d/t
d=st
Stmt1: New speed s1=5/4 s and time t1=4
s1=d/t1
d=s1*t1
s*t=s1*t1
s*t=5/4s * 4
t=5
Hence it takes 5 hours to fly from base to Hawaii island.
Sufficient.

Stmt2: avg speed=500m/hr. Not sufficient.

OA A.
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Re: What a DS!! Awesome question  [#permalink]

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New post 21 Jun 2011, 00:10
A for me too although I messed up the calculations.. grrrr
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New post 23 Jun 2011, 03:51
a d/(s*5/4) = 4 gives the value for d/s. sufficient.

b no clue about d.not sufficient.

A it is.
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Re: What a DS!! Awesome question  [#permalink]

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New post 23 Jun 2011, 23:35
A is sufficient
5v/4 = d/4

v = d/t
B we dont know the distance . so not sufficient

Answer is A.
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How long does it take a particular jet to fly from its base  [#permalink]

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New post 30 Apr 2018, 20:18
Distance remains same throughout journey

If speed becomes 5/4 then time should become 4/5 as distance is same

4/5 corresponds to 4 hrs means in actual it is 5 hours So (4/5)*5=4

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How long does it take a particular jet to fly from its base &nbs [#permalink] 30 Apr 2018, 20:18
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