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09 Aug 2025, 01:23
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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100% (00:12) correct
0% (00:00) wrong based on 1 sessions
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How many 2 × 4 × 6 boxes will fit in a 14 × 16 × 18 storage locker? (The boxes and locker are rectangular solids, and all units are in feet.)
16 Aug 2025, 04:43
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Official Explanation
To find out how many of the small boxes will fit in the large, divide the volume of the large box by the volume of the small box. Since the volume of a rectangular solid is the product of its three dimensions, the number of boxes equals
= 7 × 12 = 84.
We can save time by reducing the fractions before multiplying:
*Another equivalent approach is to reason that seven boxes that are 2 feet across will fit across a 14-foot-wide locker, while four rows of boxes that are 4 feet deep will fit in the 16-foot-deep locker, and that this 7 × 4 rectangular array of boxes can be stacked three levels high, because three boxes that are 486 feet tall will fit in an 18-foot-tall locker. 7 × 4 × 3 = 84.
Answer: 84
To find out how many of the small boxes will fit in the large, divide the volume of the large box by the volume of the small box. Since the volume of a rectangular solid is the product of its three dimensions, the number of boxes equals
= 7 × 12 = 84.
We can save time by reducing the fractions before multiplying:
*Another equivalent approach is to reason that seven boxes that are 2 feet across will fit across a 14-foot-wide locker, while four rows of boxes that are 4 feet deep will fit in the 16-foot-deep locker, and that this 7 × 4 rectangular array of boxes can be stacked three levels high, because three boxes that are 486 feet tall will fit in an 18-foot-tall locker. 7 × 4 × 3 = 84.
Answer: 84
