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10 Aug 2007, 11:04
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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How many 7 digit numbers are even and have a "3" in the hundreds place? (the number cannot start with a "0").
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10 Aug 2007, 11:32
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misterJJ2u
ABCDEFG
E can only be 3 => 1 possibility
A cannot be 0, has total of 9 possibilities
G can be 2,4,6,8,0 => 5 possibilities
the rest has 10 possibilities
Ans = 9*10*10*10*1*10*5
10 Aug 2007, 11:40
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Great approach!!!
